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x+(x-7)+(x-15)=104
We move all terms to the left:
x+(x-7)+(x-15)-(104)=0
We get rid of parentheses
x+x+x-7-15-104=0
We add all the numbers together, and all the variables
3x-126=0
We move all terms containing x to the left, all other terms to the right
3x=126
x=126/3
x=42
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