x+(y+1)+(z+2)=42

Solution for x+(y+1)+(z+2)=42 equation:

Simplifying
x + (y + 1) + (z + 2) = 42

Reorder the terms:
x + (1 + y) + (z + 2) = 42

Remove parenthesis around (1 + y)
x + 1 + y + (z + 2) = 42

Reorder the terms:
x + 1 + y + (2 + z) = 42

Remove parenthesis around (2 + z)
x + 1 + y + 2 + z = 42

Reorder the terms:
1 + 2 + x + y + z = 42

Combine like terms: 1 + 2 = 3
3 + x + y + z = 42

Solving
3 + x + y + z = 42

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + x + y + -3 + z = 42 + -3

Reorder the terms:
3 + -3 + x + y + z = 42 + -3

Combine like terms: 3 + -3 = 0
0 + x + y + z = 42 + -3
x + y + z = 42 + -3

Combine like terms: 42 + -3 = 39
x + y + z = 39

Add '-1y' to each side of the equation.
x + y + -1y + z = 39 + -1y

Combine like terms: y + -1y = 0
x + 0 + z = 39 + -1y
x + z = 39 + -1y

Add '-1z' to each side of the equation.
x + z + -1z = 39 + -1y + -1z

Combine like terms: z + -1z = 0
x + 0 = 39 + -1y + -1z
x = 39 + -1y + -1z

Simplifying
x = 39 + -1y + -1z