x+(y+z)=(x+y)+z

Solution for x+(y+z)=(x+y)+z equation:

Simplifying
x + (y + z) = (x + y) + z

Remove parenthesis around (y + z)
x + y + z = (x + y) + z

Remove parenthesis around (x + y)
x + y + z = x + y + z

Add '-1x' to each side of the equation.
x + y + -1x + z = x + y + -1x + z

Reorder the terms:
x + -1x + y + z = x + y + -1x + z

Combine like terms: x + -1x = 0
0 + y + z = x + y + -1x + z
y + z = x + y + -1x + z

Reorder the terms:
y + z = x + -1x + y + z

Combine like terms: x + -1x = 0
y + z = 0 + y + z
y + z = y + z

Add '-1y' to each side of the equation.
y + -1y + z = y + -1y + z

Combine like terms: y + -1y = 0
0 + z = y + -1y + z
z = y + -1y + z

Combine like terms: y + -1y = 0
z = 0 + z
z = z

Add '-1z' to each side of the equation.
z + -1z = z + -1z

Combine like terms: z + -1z = 0
0 = z + -1z

Combine like terms: z + -1z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.