x+0.07x+.10x(x+0.07)=45.00

Solution for x+0.07x+.10x(x+0.07)=45.00 equation:

x+0.07x+.10x(x+0.07)=45.00

We move all terms to the left:

x+0.07x+.10x(x+0.07)-(45.00)=0

We add all the numbers together, and all the variables

x+0.07x+.10x(x+0.07)-45=0

We add all the numbers together, and all the variables

1.07x+.10x(x+0.07)-45=0

We multiply parentheses

x^2+1.07x+0.07x-45=0

We add all the numbers together, and all the variables

x^2+1.14x-45=0

a = 1; b = 1.14; c = -45;
Δ = b2-4ac
Δ = 1.142-4·1·(-45)
Δ = 181.2996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.14)-\sqrt{181.2996}}{2*1}=\frac{-1.14-\sqrt{181.2996}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.14)+\sqrt{181.2996}}{2*1}=\frac{-1.14+\sqrt{181.2996}}{2}
$