x+0.5=(3x+1.5)+(3x-2)

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Solution for x+0.5=(3x+1.5)+(3x-2) equation: 



x+0.5=(3x+1.5)+(3x-2)

We move all terms to the left:

x+0.5-((3x+1.5)+(3x-2))=0



We calculate terms in parentheses: -((3x+1.5)+(3x-2)), so:

(3x+1.5)+(3x-2)

We get rid of parentheses

3x+3x+1.5-2

We add all the numbers together, and all the variables

6x-0.5

Back to the equation:

-(6x-0.5)



We get rid of parentheses

x-6x+0.5+0.5=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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