x+1-(1-2x)=3+x-1-(x-4)

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Solution for x+1-(1-2x)=3+x-1-(x-4) equation: 



x+1-(1-2x)=3+x-1-(x-4)

We move all terms to the left:

x+1-(1-2x)-(3+x-1-(x-4))=0

We add all the numbers together, and all the variables

x-(-2x+1)-(3+x-1-(x-4))+1=0

We get rid of parentheses

x+2x-(3+x-1-(x-4))-1+1=0



We calculate terms in parentheses: -(3+x-1-(x-4)), so:

3+x-1-(x-4)

determiningTheFunctionDomain
x-(x-4)+3-1

We add all the numbers together, and all the variables

x-(x-4)+2

We get rid of parentheses

x-x+4+2

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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