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x+1-(x-1)+x-1+x+1=1-(x-1)
We move all terms to the left:
x+1-(x-1)+x-1+x+1-(1-(x-1))=0
We add all the numbers together, and all the variables
3x-(x-1)-(1-(x-1))+1=0
We get rid of parentheses
3x-x-(1-(x-1))+1+1=0
We calculate terms in parentheses: -(1-(x-1)), so:We add all the numbers together, and all the variables
1-(x-1)
determiningTheFunctionDomain -(x-1)+1
We get rid of parentheses
-x+1+1
We add all the numbers together, and all the variables
-1x+2
Back to the equation:
-(-1x+2)
2x-(-1x+2)+2=0
We get rid of parentheses
2x+1x-2+2=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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