x+1.4x(x+35)+(x-5)=360

Solution for x+1.4x(x+35)+(x-5)=360 equation:

x+1.4x(x+35)+(x-5)=360

We move all terms to the left:

x+1.4x(x+35)+(x-5)-(360)=0

We multiply parentheses

x^2+x+35x+(x-5)-360=0

We get rid of parentheses

x^2+x+35x+x-5-360=0

We add all the numbers together, and all the variables

x^2+37x-365=0

a = 1; b = 37; c = -365;
Δ = b2-4ac
Δ = 372-4·1·(-365)
Δ = 2829
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{2829}}{2*1}=\frac{-37-\sqrt{2829}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{2829}}{2*1}=\frac{-37+\sqrt{2829}}{2}
$