x+1/2x+5=x+3/3x+4

Solution for x+1/2x+5=x+3/3x+4 equation:

x+1/2x+5=x+3/3x+4

We move all terms to the left:

x+1/2x+5-(x+3/3x+4)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x+4)!=0

x∈R


We get rid of parentheses

x+1/2x-x-3/3x-4+5=0

We calculate fractions


x-x+3x/6x^2+(-6x)/6x^2-4+5=0

We add all the numbers together, and all the variables

3x/6x^2+(-6x)/6x^2+1=0

We multiply all the terms by the denominator


3x+(-6x)+1*6x^2=0

Wy multiply elements

6x^2+3x+(-6x)=0

We get rid of parentheses

6x^2+3x-6x=0

We add all the numbers together, and all the variables

6x^2-3x=0

a = 6; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·6·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*6}=\frac{0}{12}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*6}=\frac{6}{12}
=1/2
$