x+1/3=(x-3)/5

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Solution for x+1/3=(x-3)/5 equation: 



x+1/3=(x-3)/5

We move all terms to the left:

x+1/3-((x-3)/5)=0

We calculate fractions


x+(-((x-3)*3)/()+()/()=0



We calculate terms in parentheses: +(-((x-3)*3)/()+()/(), so:

-((x-3)*3)/()+()/(

We add all the numbers together, and all the variables

-((x-3)*3)/()+1

We multiply all the terms by the denominator


-((x-3)*3)+1*()



We calculate terms in parentheses: -((x-3)*3), so:

(x-3)*3

We multiply parentheses

3x-9

Back to the equation:

-(3x-9)



We add all the numbers together, and all the variables

-(3x-9)

We get rid of parentheses

-3x+9

Back to the equation:

+(-3x+9)



We get rid of parentheses

x-3x+9=0

We add all the numbers together, and all the variables

-2x+9=0

We move all terms containing x to the left, all other terms to the right

-2x=-9

x=-9/-2

x=4+1/2

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