x+1/3x+(1/3)x-4+2(1/3x-4)=72

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Solution for x+1/3x+(1/3)x-4+2(1/3x-4)=72 equation: 



x+1/3x+(1/3)x-4+2(1/3x-4)=72

We move all terms to the left:

x+1/3x+(1/3)x-4+2(1/3x-4)-(72)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3x-4)!=0

x∈R



We add all the numbers together, and all the variables

x+1/3x+(+1/3)x+2(1/3x-4)-4-72=0

We add all the numbers together, and all the variables

x+1/3x+(+1/3)x+2(1/3x-4)-76=0

We multiply parentheses

x^2+x+1/3x+2x-8-76=0

We multiply all the terms by the denominator


x^2*3x+x*3x+2x*3x-8*3x-76*3x+1=0

Wy multiply elements

3x^3+3x^2+6x^2-24x-228x+1=0

We do not support expression: x^3

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