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x+1/3x+2/3x-4=30
We move all terms to the left:
x+1/3x+2/3x-4-(30)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+1/3x+2/3x-34=0
We multiply all the terms by the denominator
x*3x-34*3x+1+2=0
We add all the numbers together, and all the variables
x*3x-34*3x+3=0
Wy multiply elements
3x^2-102x+3=0
a = 3; b = -102; c = +3;
Δ = b2-4ac
Δ = -1022-4·3·3
Δ = 10368
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10368}=\sqrt{5184*2}=\sqrt{5184}*\sqrt{2}=72\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-72\sqrt{2}}{2*3}=\frac{102-72\sqrt{2}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+72\sqrt{2}}{2*3}=\frac{102+72\sqrt{2}}{6} $
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