If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x+1/3x+2x=90
We move all terms to the left:
x+1/3x+2x-(90)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
3x+1/3x-90=0
We multiply all the terms by the denominator
3x*3x-90*3x+1=0
Wy multiply elements
9x^2-270x+1=0
a = 9; b = -270; c = +1;
Δ = b2-4ac
Δ = -2702-4·9·1
Δ = 72864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72864}=\sqrt{144*506}=\sqrt{144}*\sqrt{506}=12\sqrt{506}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-270)-12\sqrt{506}}{2*9}=\frac{270-12\sqrt{506}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-270)+12\sqrt{506}}{2*9}=\frac{270+12\sqrt{506}}{18} $
| (p-3)(p+5)=0 | | 5n^2-3n=2 | | 14x-8=8x-44 | | x+x+.5x+.25x=300 | | 15^-5x=3 | | 2(x-3)-1=3(x+2)-14 | | x^2+8x+6=3x+2 | | x^2+7x+7=3x+3 | | x-(x+3)=-x-19 | | x^2-x+10=4x+4 | | x^2-x+5=4x+1 | | x^2+8x+10=2x+1 | | x^2-3x+13=4x+1 | | x-(x-1)=-x+2 | | 10x+2x=12 | | T=-5t²+15t+20 | | x-(10x+1)=7-5(3x+4) | | -4x+54=x+14 | | -4x+9=x+4 | | 6x-12+21=39 | | 5x-11=3x+24 | | (8x-13)=(7x-17)=180 | | x^2+x+5=5x+2 | | x^2/99/2=0 | | x^2-3x+5=x+1 | | (8x-13)=(7x-17) | | x^2+7=5x+3 | | 5x-45=20x+30 | | (7x+49)=(2x+94) | | 5x-3(2x+8)=-22 | | 2z-20=15 | | 3x-x+1=3x-1 |