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x+1/3x+5=105
We move all terms to the left:
x+1/3x+5-(105)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
x+1/3x-100=0
We multiply all the terms by the denominator
x*3x-100*3x+1=0
Wy multiply elements
3x^2-300x+1=0
a = 3; b = -300; c = +1;
Δ = b2-4ac
Δ = -3002-4·3·1
Δ = 89988
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{89988}=\sqrt{4*22497}=\sqrt{4}*\sqrt{22497}=2\sqrt{22497}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-2\sqrt{22497}}{2*3}=\frac{300-2\sqrt{22497}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+2\sqrt{22497}}{2*3}=\frac{300+2\sqrt{22497}}{6} $
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