x+1/x+2=5/3

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Solution for x+1/x+2=5/3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+1/x+2 = 5/3 // - 5/3

x+1/x-(5/3)+2 = 0

x+1/x-5/3+2 = 0

1*x^1+1*x^-1+1/3*x^0 = 0

(1*x^2+1/3*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2+1/3*x^1+1*x^0) = 0

x^1

x^2+(1/3)*x+1 = 0

x^2+(1/3)*x+1 = 0

DELTA = (1/3)^2-(1*1*4)

DELTA = -35/9

DELTA < 0

x in { } 

x belongs to the empty set

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