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x+1/x-2+3=3/x-2
We move all terms to the left:
x+1/x-2+3-(3/x-2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-2)!=0We add all the numbers together, and all the variables
x∈R
x+1/x-(3/x-2)+1=0
We get rid of parentheses
x+1/x-3/x+2+1=0
We multiply all the terms by the denominator
x*x+2*x+1*x+1-3=0
We add all the numbers together, and all the variables
3x+x*x-2=0
Wy multiply elements
x^2+3x-2=0
a = 1; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·1·(-2)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{17}}{2*1}=\frac{-3-\sqrt{17}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{17}}{2*1}=\frac{-3+\sqrt{17}}{2} $
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