x+10-2/3x=20

Solution for x+10-2/3x=20 equation:

x+10-2/3x=20

We move all terms to the left:

x+10-2/3x-(20)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x-2/3x-10=0

We multiply all the terms by the denominator


x*3x-10*3x-2=0

Wy multiply elements

3x^2-30x-2=0

a = 3; b = -30; c = -2;
Δ = b2-4ac
Δ = -302-4·3·(-2)
Δ = 924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{924}=\sqrt{4*231}=\sqrt{4}*\sqrt{231}=2\sqrt{231}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{231}}{2*3}=\frac{30-2\sqrt{231}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{231}}{2*3}=\frac{30+2\sqrt{231}}{6}
$