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x+10x(x+60)=180
We move all terms to the left:
x+10x(x+60)-(180)=0
We multiply parentheses
10x^2+x+600x-180=0
We add all the numbers together, and all the variables
10x^2+601x-180=0
a = 10; b = 601; c = -180;
Δ = b2-4ac
Δ = 6012-4·10·(-180)
Δ = 368401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(601)-\sqrt{368401}}{2*10}=\frac{-601-\sqrt{368401}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(601)+\sqrt{368401}}{2*10}=\frac{-601+\sqrt{368401}}{20} $
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