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x+11/2x-5=2
We move all terms to the left:
x+11/2x-5-(2)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x+11/2x-7=0
We multiply all the terms by the denominator
x*2x-7*2x+11=0
Wy multiply elements
2x^2-14x+11=0
a = 2; b = -14; c = +11;
Δ = b2-4ac
Δ = -142-4·2·11
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6\sqrt{3}}{2*2}=\frac{14-6\sqrt{3}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6\sqrt{3}}{2*2}=\frac{14+6\sqrt{3}}{4} $
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