x+12+2(x-5)=2(3x-2)

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Solution for x+12+2(x-5)=2(3x-2) equation: 



x+12+2(x-5)=2(3x-2)

We move all terms to the left:

x+12+2(x-5)-(2(3x-2))=0

We multiply parentheses

x+2x-(2(3x-2))-10+12=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

3x-(6x-4)+2=0

We get rid of parentheses

3x-6x+4+2=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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