x+12-3(2-3x)=7x+9-(-3)(1-3x)(2)

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Solution for x+12-3(2-3x)=7x+9-(-3)(1-3x)(2) equation: 



x+12-3(2-3x)=7x+9-(-3)(1-3x)(2)

We move all terms to the left:

x+12-3(2-3x)-(7x+9-(-3)(1-3x)(2))=0

We add all the numbers together, and all the variables

x-3(-3x+2)-(7x+9-(-3)(-3x+1)2)+12=0

We multiply parentheses

x+9x-(7x+9-(-3)(-3x+1)2)-6+12=0

We multiply parentheses ..

x+9x-(7x+9-(+9x-3)2)-6+12=0



We calculate terms in parentheses: -(7x+9-(+9x-3)2), so:

7x+9-(+9x-3)2

determiningTheFunctionDomain
7x-(+9x-3)2+9

We add all the numbers together, and all the variables

7x-(9x-3)2+9

We multiply parentheses

7x-18x+6+9

We add all the numbers together, and all the variables

-11x+15

Back to the equation:

-(-11x+15)



We add all the numbers together, and all the variables

10x-(-11x+15)+6=0

We get rid of parentheses

10x+11x-15+6=0

We add all the numbers together, and all the variables

21x-9=0

We move all terms containing x to the left, all other terms to the right

21x=9

x=9/21

x=3/7

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