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x+12=35-(x+12)
We move all terms to the left:
x+12-(35-(x+12))=0
We calculate terms in parentheses: -(35-(x+12)), so:We get rid of parentheses
35-(x+12)
determiningTheFunctionDomain -(x+12)+35
We get rid of parentheses
-x-12+35
We add all the numbers together, and all the variables
-1x+23
Back to the equation:
-(-1x+23)
x+1x-23+12=0
We add all the numbers together, and all the variables
2x-11=0
We move all terms containing x to the left, all other terms to the right
2x=11
x=11/2
x=5+1/2
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