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x+12=7/6(x)
We move all terms to the left:
x+12-(7/6(x))=0
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+7/6x)+12=0
We get rid of parentheses
x-7/6x+12=0
We multiply all the terms by the denominator
x*6x+12*6x-7=0
Wy multiply elements
6x^2+72x-7=0
a = 6; b = 72; c = -7;
Δ = b2-4ac
Δ = 722-4·6·(-7)
Δ = 5352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5352}=\sqrt{4*1338}=\sqrt{4}*\sqrt{1338}=2\sqrt{1338}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-2\sqrt{1338}}{2*6}=\frac{-72-2\sqrt{1338}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+2\sqrt{1338}}{2*6}=\frac{-72+2\sqrt{1338}}{12} $
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