x+14/x-3=-1/2

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Solution for x+14/x-3=-1/2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+14/x-3 = -1/2 // + -1/2

x+14/x-(-1/2)-3 = 0

x+14/x+1/2-3 = 0

1*x^1+14*x^-1-5/2*x^0 = 0

(1*x^2-5/2*x^1+14*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-5/2*x^1+14*x^0) = 0

x^1

x^2+(-5/2)*x+14 = 0

x^2+(-5/2)*x+14 = 0

DELTA = (-5/2)^2-(1*4*14)

DELTA = -199/4

DELTA < 0

x in { } 

x belongs to the empty set

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