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x+15)=3/5(2x+15)
We move all terms to the left:
x+15)-(3/5(2x+15))=0
Domain of the equation: 5(2x+15))!=0We multiply all the terms by the denominator
x∈R
x*5(2x+15))+15)-(3=0
Wy multiply elements
5x^2(2=0
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