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x+19=3(5+x)
We move all terms to the left:
x+19-(3(5+x))=0
We add all the numbers together, and all the variables
x-(3(x+5))+19=0
We calculate terms in parentheses: -(3(x+5)), so:We get rid of parentheses
3(x+5)
We multiply parentheses
3x+15
Back to the equation:
-(3x+15)
x-3x-15+19=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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