x+1=(2x+100)/7

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Solution for x+1=(2x+100)/7 equation: 



x+1=(2x+100)/7

We move all terms to the left:

x+1-((2x+100)/7)=0

We multiply all the terms by the denominator


x*7)-((2x+100)+1*7)=0

We add all the numbers together, and all the variables

x*7)-((2x+100)=0

Wy multiply elements

7x^2=0

a = 7; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·7·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{14}=0$

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