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x+1=x-+(-5)
We move all terms to the left:
x+1-(x-+(-5))=0
We use the square of the difference formula
x-(x-(-5))+1=0
We calculate terms in parentheses: -(x-(-5)), so:We get rid of parentheses
x-(-5)
We add all the numbers together, and all the variables
x+5
Back to the equation:
-(x+5)
x-x-5+1=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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