x+1=x2+2x-11

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Solution for x+1=x2+2x-11 equation:



x+1=x2+2x-11
We move all terms to the left:
x+1-(x2+2x-11)=0
We add all the numbers together, and all the variables
-(+x^2+2x-11)+x+1=0
We get rid of parentheses
-x^2-2x+x+11+1=0
We add all the numbers together, and all the variables
-1x^2-1x+12=0
a = -1; b = -1; c = +12;
Δ = b2-4ac
Δ = -12-4·(-1)·12
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-7}{2*-1}=\frac{-6}{-2} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+7}{2*-1}=\frac{8}{-2} =-4 $

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