x+2((x/5)+2)=99

Solution for x+2((x/5)+2)=99 equation:

x+2((x/5)+2)=99

We move all terms to the left:

x+2((x/5)+2)-(99)=0

We add all the numbers together, and all the variables

x+2((+x/5)+2)-99=0

We multiply all the terms by the denominator


x*5)+2)+2((+x-99*5)+2)=0

We add all the numbers together, and all the variables

x*5)+2)+2((x-495)+2)=0

We add all the numbers together, and all the variables

x*5)+2)+2((x=0

Wy multiply elements

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$