x+2(1x+2)=16

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Solution for x+2(1x+2)=16 equation: 



x+2(1x+2)=16

We move all terms to the left:

x+2(1x+2)-(16)=0

We add all the numbers together, and all the variables

x+2(x+2)-16=0

We multiply parentheses

x+2x+4-16=0

We add all the numbers together, and all the variables

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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