x+2(3x+1)=3(x-21)

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Solution for x+2(3x+1)=3(x-21) equation: 



x+2(3x+1)=3(x-21)

We move all terms to the left:

x+2(3x+1)-(3(x-21))=0

We multiply parentheses

x+6x-(3(x-21))+2=0



We calculate terms in parentheses: -(3(x-21)), so:

3(x-21)

We multiply parentheses

3x-63

Back to the equation:

-(3x-63)



We add all the numbers together, and all the variables

7x-(3x-63)+2=0

We get rid of parentheses

7x-3x+63+2=0

We add all the numbers together, and all the variables

4x+65=0

We move all terms containing x to the left, all other terms to the right

4x=-65

x=-65/4

x=-16+1/4

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