x+2(x+1)=4(x-2)

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Solution for x+2(x+1)=4(x-2) equation:



x+2(x+1)=4(x-2)
We move all terms to the left:
x+2(x+1)-(4(x-2))=0
We multiply parentheses
x+2x-(4(x-2))+2=0
We calculate terms in parentheses: -(4(x-2)), so:
4(x-2)
We multiply parentheses
4x-8
Back to the equation:
-(4x-8)
We add all the numbers together, and all the variables
3x-(4x-8)+2=0
We get rid of parentheses
3x-4x+8+2=0
We add all the numbers together, and all the variables
-1x+10=0
We move all terms containing x to the left, all other terms to the right
-x=-10
x=-10/-1
x=+10

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