x+2(x+10)=(x+3)+5

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Solution for x+2(x+10)=(x+3)+5 equation: 



x+2(x+10)=(x+3)+5

We move all terms to the left:

x+2(x+10)-((x+3)+5)=0

We multiply parentheses

x+2x-((x+3)+5)+20=0



We calculate terms in parentheses: -((x+3)+5), so:

(x+3)+5

We get rid of parentheses

x+3+5

We add all the numbers together, and all the variables

x+8

Back to the equation:

-(x+8)



We add all the numbers together, and all the variables

3x-(x+8)+20=0

We get rid of parentheses

3x-x-8+20=0

We add all the numbers together, and all the variables

2x+12=0

We move all terms containing x to the left, all other terms to the right

2x=-12

x=-12/2

x=-6

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