x+2(x+10)=2-6(x+3)

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Solution for x+2(x+10)=2-6(x+3) equation: 



x+2(x+10)=2-6(x+3)

We move all terms to the left:

x+2(x+10)-(2-6(x+3))=0

We multiply parentheses

x+2x-(2-6(x+3))+20=0



We calculate terms in parentheses: -(2-6(x+3)), so:

2-6(x+3)

determiningTheFunctionDomain
-6(x+3)+2

We multiply parentheses

-6x-18+2

We add all the numbers together, and all the variables

-6x-16

Back to the equation:

-(-6x-16)



We add all the numbers together, and all the variables

3x-(-6x-16)+20=0

We get rid of parentheses

3x+6x+16+20=0

We add all the numbers together, and all the variables

9x+36=0

We move all terms containing x to the left, all other terms to the right

9x=-36

x=-36/9

x=-4

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