x+2(x+2)+3(x+4)=58

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Solution for x+2(x+2)+3(x+4)=58 equation: 


Simplifying
x + 2(x + 2) + 3(x + 4) = 58

Reorder the terms:
x + 2(2 + x) + 3(x + 4) = 58
x + (2 * 2 + x * 2) + 3(x + 4) = 58
x + (4 + 2x) + 3(x + 4) = 58

Reorder the terms:
x + 4 + 2x + 3(4 + x) = 58
x + 4 + 2x + (4 * 3 + x * 3) = 58
x + 4 + 2x + (12 + 3x) = 58

Reorder the terms:
4 + 12 + x + 2x + 3x = 58

Combine like terms: 4 + 12 = 16
16 + x + 2x + 3x = 58

Combine like terms: x + 2x = 3x
16 + 3x + 3x = 58

Combine like terms: 3x + 3x = 6x
16 + 6x = 58

Solving
16 + 6x = 58

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + 6x = 58 + -16

Combine like terms: 16 + -16 = 0
0 + 6x = 58 + -16
6x = 58 + -16

Combine like terms: 58 + -16 = 42
6x = 42

Divide each side by '6'.
x = 7

Simplifying
x = 7

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