x+2(x+2)=20+(x+4)

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Solution for x+2(x+2)=20+(x+4) equation: 



x+2(x+2)=20+(x+4)

We move all terms to the left:

x+2(x+2)-(20+(x+4))=0

We multiply parentheses

x+2x-(20+(x+4))+4=0



We calculate terms in parentheses: -(20+(x+4)), so:

20+(x+4)

determiningTheFunctionDomain
(x+4)+20

We get rid of parentheses

x+4+20

We add all the numbers together, and all the variables

x+24

Back to the equation:

-(x+24)



We add all the numbers together, and all the variables

3x-(x+24)+4=0

We get rid of parentheses

3x-x-24+4=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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