x+2(x-1)-3(x-2)=4(x-3)

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Solution for x+2(x-1)-3(x-2)=4(x-3) equation: 



x+2(x-1)-3(x-2)=4(x-3)

We move all terms to the left:

x+2(x-1)-3(x-2)-(4(x-3))=0

We multiply parentheses

x+2x-3x-(4(x-3))-2+6=0



We calculate terms in parentheses: -(4(x-3)), so:

4(x-3)

We multiply parentheses

4x-12

Back to the equation:

-(4x-12)



We add all the numbers together, and all the variables

-(4x-12)+4=0

We get rid of parentheses

-4x+12+4=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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