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x+2(x-1)=2x+3(x-2)
We move all terms to the left:
x+2(x-1)-(2x+3(x-2))=0
We multiply parentheses
x+2x-(2x+3(x-2))-2=0
We calculate terms in parentheses: -(2x+3(x-2)), so:We add all the numbers together, and all the variables
2x+3(x-2)
We multiply parentheses
2x+3x-6
We add all the numbers together, and all the variables
5x-6
Back to the equation:
-(5x-6)
3x-(5x-6)-2=0
We get rid of parentheses
3x-5x+6-2=0
We add all the numbers together, and all the variables
-2x+4=0
We move all terms containing x to the left, all other terms to the right
-2x=-4
x=-4/-2
x=+2
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