x+2(x-3)+1=3(x+1)-x

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Solution for x+2(x-3)+1=3(x+1)-x equation: 



x+2(x-3)+1=3(x+1)-x

We move all terms to the left:

x+2(x-3)+1-(3(x+1)-x)=0

We multiply parentheses

x+2x-(3(x+1)-x)-6+1=0



We calculate terms in parentheses: -(3(x+1)-x), so:

3(x+1)-x

We add all the numbers together, and all the variables

-1x+3(x+1)

We multiply parentheses

-1x+3x+3

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

3x-(2x+3)-5=0

We get rid of parentheses

3x-2x-3-5=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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