x+2(x-4)=1+3(x-2)

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Solution for x+2(x-4)=1+3(x-2) equation:


Simplifying
x + 2(x + -4) = 1 + 3(x + -2)

Reorder the terms:
x + 2(-4 + x) = 1 + 3(x + -2)
x + (-4 * 2 + x * 2) = 1 + 3(x + -2)
x + (-8 + 2x) = 1 + 3(x + -2)

Reorder the terms:
-8 + x + 2x = 1 + 3(x + -2)

Combine like terms: x + 2x = 3x
-8 + 3x = 1 + 3(x + -2)

Reorder the terms:
-8 + 3x = 1 + 3(-2 + x)
-8 + 3x = 1 + (-2 * 3 + x * 3)
-8 + 3x = 1 + (-6 + 3x)

Combine like terms: 1 + -6 = -5
-8 + 3x = -5 + 3x

Add '-3x' to each side of the equation.
-8 + 3x + -3x = -5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-8 + 0 = -5 + 3x + -3x
-8 = -5 + 3x + -3x

Combine like terms: 3x + -3x = 0
-8 = -5 + 0
-8 = -5

Solving
-8 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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