x+2(x-5)=3(x-2)-4

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Solution for x+2(x-5)=3(x-2)-4 equation: 


Simplifying
x + 2(x + -5) = 3(x + -2) + -4

Reorder the terms:
x + 2(-5 + x) = 3(x + -2) + -4
x + (-5 * 2 + x * 2) = 3(x + -2) + -4
x + (-10 + 2x) = 3(x + -2) + -4

Reorder the terms:
-10 + x + 2x = 3(x + -2) + -4

Combine like terms: x + 2x = 3x
-10 + 3x = 3(x + -2) + -4

Reorder the terms:
-10 + 3x = 3(-2 + x) + -4
-10 + 3x = (-2 * 3 + x * 3) + -4
-10 + 3x = (-6 + 3x) + -4

Reorder the terms:
-10 + 3x = -6 + -4 + 3x

Combine like terms: -6 + -4 = -10
-10 + 3x = -10 + 3x

Add '10' to each side of the equation.
-10 + 10 + 3x = -10 + 10 + 3x

Combine like terms: -10 + 10 = 0
0 + 3x = -10 + 10 + 3x
3x = -10 + 10 + 3x

Combine like terms: -10 + 10 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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