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x+2/3x=1880
We move all terms to the left:
x+2/3x-(1880)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x*3x-1880*3x+2=0
Wy multiply elements
3x^2-5640x+2=0
a = 3; b = -5640; c = +2;
Δ = b2-4ac
Δ = -56402-4·3·2
Δ = 31809576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31809576}=\sqrt{4*7952394}=\sqrt{4}*\sqrt{7952394}=2\sqrt{7952394}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5640)-2\sqrt{7952394}}{2*3}=\frac{5640-2\sqrt{7952394}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5640)+2\sqrt{7952394}}{2*3}=\frac{5640+2\sqrt{7952394}}{6} $
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