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x+2/5x=210
We move all terms to the left:
x+2/5x-(210)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-210*5x+2=0
Wy multiply elements
5x^2-1050x+2=0
a = 5; b = -1050; c = +2;
Δ = b2-4ac
Δ = -10502-4·5·2
Δ = 1102460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1102460}=\sqrt{4*275615}=\sqrt{4}*\sqrt{275615}=2\sqrt{275615}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1050)-2\sqrt{275615}}{2*5}=\frac{1050-2\sqrt{275615}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1050)+2\sqrt{275615}}{2*5}=\frac{1050+2\sqrt{275615}}{10} $
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