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x+2/5x=307
We move all terms to the left:
x+2/5x-(307)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
x*5x-307*5x+2=0
Wy multiply elements
5x^2-1535x+2=0
a = 5; b = -1535; c = +2;
Δ = b2-4ac
Δ = -15352-4·5·2
Δ = 2356185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1535)-\sqrt{2356185}}{2*5}=\frac{1535-\sqrt{2356185}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1535)+\sqrt{2356185}}{2*5}=\frac{1535+\sqrt{2356185}}{10} $
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