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x+2/x+14=10/x-10
We move all terms to the left:
x+2/x+14-(10/x-10)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x-10)!=0We get rid of parentheses
x∈R
x+2/x-10/x+10+14=0
We multiply all the terms by the denominator
x*x+10*x+14*x+2-10=0
We add all the numbers together, and all the variables
24x+x*x-8=0
Wy multiply elements
x^2+24x-8=0
a = 1; b = 24; c = -8;
Δ = b2-4ac
Δ = 242-4·1·(-8)
Δ = 608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{608}=\sqrt{16*38}=\sqrt{16}*\sqrt{38}=4\sqrt{38}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{38}}{2*1}=\frac{-24-4\sqrt{38}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{38}}{2*1}=\frac{-24+4\sqrt{38}}{2} $
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