x+2/x-2=-3/x

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Solution for x+2/x-2=-3/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+2/x-2 = -3/x // + -3/x

x+2/x-(-3/x)-2 = 0

x+2/x+3*x^-1-2 = 0

1*x^1+5*x^-1-2*x^0 = 0

(1*x^2-2*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-2*x^1+5*x^0) = 0

x^1

x^2-2*x+5 = 0

x^2-2*x+5 = 0

DELTA = (-2)^2-(1*4*5)

DELTA = -16

DELTA < 0

x in { } 

x belongs to the empty set

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