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x+20=1/2(x)
We move all terms to the left:
x+20-(1/2(x))=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+1/2x)+20=0
We get rid of parentheses
x-1/2x+20=0
We multiply all the terms by the denominator
x*2x+20*2x-1=0
Wy multiply elements
2x^2+40x-1=0
a = 2; b = 40; c = -1;
Δ = b2-4ac
Δ = 402-4·2·(-1)
Δ = 1608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1608}=\sqrt{4*402}=\sqrt{4}*\sqrt{402}=2\sqrt{402}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{402}}{2*2}=\frac{-40-2\sqrt{402}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{402}}{2*2}=\frac{-40+2\sqrt{402}}{4} $
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