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x+21/2x+20=55
We move all terms to the left:
x+21/2x+20-(55)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
x+21/2x-35=0
We multiply all the terms by the denominator
x*2x-35*2x+21=0
Wy multiply elements
2x^2-70x+21=0
a = 2; b = -70; c = +21;
Δ = b2-4ac
Δ = -702-4·2·21
Δ = 4732
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4732}=\sqrt{676*7}=\sqrt{676}*\sqrt{7}=26\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-26\sqrt{7}}{2*2}=\frac{70-26\sqrt{7}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+26\sqrt{7}}{2*2}=\frac{70+26\sqrt{7}}{4} $
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