x+22+4x=6(2x+5)+6

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Solution for x+22+4x=6(2x+5)+6 equation: 



x+22+4x=6(2x+5)+6

We move all terms to the left:

x+22+4x-(6(2x+5)+6)=0

We add all the numbers together, and all the variables

5x-(6(2x+5)+6)+22=0



We calculate terms in parentheses: -(6(2x+5)+6), so:

6(2x+5)+6

We multiply parentheses

12x+30+6

We add all the numbers together, and all the variables

12x+36

Back to the equation:

-(12x+36)



We get rid of parentheses

5x-12x-36+22=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2

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